It seems the image content is missing, but based on common similar problems (e.g., given (3a = 5b)), here's a typical solution:

Assumption (common scenario):

Suppose (3a = 5b), so (\frac{a}{b} = \frac{5}{3}). Let (a = 5k) and (b = 3k) ((k≠0)).

Calculate (\frac{a+b}{a-b}):

[ \frac{a+b}{a-b} = \frac{5k + 3k}{5k - 3k} = \frac{8k}{2k} = 4 ]

Answer: (\boxed{4})

(Note: If the original problem differs, adjust based on the actual equations, but this is a common result.)

(\boxed{4})

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