To solve the problem of finding the probability that the sum of two randomly picked balls (marked 1-100) is even, follow these steps:
Key Observation:
The sum of two numbers is even if and only if both numbers are even OR both are odd.
Step 1: Count even and odd numbers
From 1 to 100:
- Even numbers: 50 (2,4,...,100)
- Odd numbers: 50 (1,3,...,99)
Step 2: Calculate favorable outcomes
Number of ways to pick 2 even balls: $\binom{50}{2} = \frac{50×49}{2} = 1225$
Number of ways to pick 2 odd balls: $\binom{50}{2} = 1225$
Total favorable outcomes: $1225 + 1225 = 2450$
Step 3: Total possible outcomes
Number of ways to pick 2 balls from 100: $\binom{100}{2} = \frac{100×99}{2} = 4950$
Step 4: Compute probability
Probability = $\frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{2450}{4950} = \frac{49}{99}$
Answer: $\boxed{\dfrac{49}{99}}$


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